First slide

Vectors

Question

A force is inclined at $60^{0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately

Moderate

A

25 N
B

84 N
C

87 N
D

90 N

Solution

$R_{x} = 50 = Rcos 60^{0} \Rightarrow R = 100 N$
$R_{y} = Rsin 60^{0} = \frac{100 \sqrt{3}}{2} = 50 \sqrt{3 N}$
= 86.6 N $\approx$ 87 N

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