A force is inclined at 600 to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately
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a
25 N
b
84 N
c
87 N
d
90 N
answer is C.
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Detailed Solution
Rx = 50 = Rcos600 ⇒ R = 100 NRy = Rsin600 = 10032 = 503 N= 86.6 N ≈87 N