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A force is inclined at $60^{0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately

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25 N

84 N

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90 N

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detailed solution

Correct option is C

Rx = 50 = Rcos600 ⇒ R = 100 NRy = Rsin600 = 10032 = 503 N= 86.6 N ≈87 N

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A force is inclined at 600 to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately

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A force is inclined at $60^{0}$ to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately