A force is inclined at 60o to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately

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25 N

84 N

87 N

90 N

answer is C.

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Detailed Solution

Rx=50=Rcos⁡60∘⇒R=100NRy=Rsin⁡60∘=10032=503N=86.6N≃87N

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