First slide

Scalars and Vectors

Question

A force is inclined at 60^o to the horizontal. If its rectangular component in the horizontal direction is 50 N, then magnitude of the vertical component of force is approximately

Moderate

A

25 N
B

84 N
C

87 N
D

90 N

Solution

$\begin{array}{l} R_{x} = 50 = R \cos 60^{\circ} \Rightarrow R = 100 N \\ R_{y} = R \sin 60^{\circ} = \frac{100 \sqrt{3}}{2} = 50 \sqrt{3} N \\ = 86.6 N ≃ 87 N \end{array}$

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