First slide

Work

Question

A force of 100N is acting on a 10kg block at 60^o above the horizontal. If it travels 5m in 10s work done by force is

Easy

A

500J
B

250J
C

2500J
D

150J

Solution

$\begin{array}{l} w = Fscos θ \\ 100 \times 5 \times \cos 60 = 100 \times 5 \times \frac{1}{2} \\ W = 250 J \end{array}$

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