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Q.

A force of 5 N acts on a 15 kg body initially at rest. The work done by the force during the first second of motion of the body is a

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a

5 J

b

56J

c

6 J

d

75 J

answer is B.

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Detailed Solution

W=Fs=F×12at2 from s=ut+12at2⇒W=F12Fmt2=F2t22m=25×(1)22×15=2530=56J
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