First slide

Connected bodies

Question

Force of 3N acts on a system of two blocks of mass 2 kg and 1 kg as shown in figure. Contact force between the blocks is :

Easy

A

1N
B

2N
C

3N
D

0

Solution

Acceleration $= \frac{3 N}{2 kg + 1 kg} = 1 m / s^{2}$
Contact for between blocks
= m₂a= (1kg) (1m/s²) = 1N

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