Questions
A force of 100 N is applied on a block of mass 3 kg as shown in the figure. The coefficient of friction between the surface and the block is . The acceleration of block is
detailed solution
Correct option is A
Normal reaction on the block N = 100 cos 300 = 50 3 N ⇒fmax=μN = 50 N Vertical component of applied force = 100 sin 300 N =50 N Since weight of the block is equal to fmax , net force on the block is zero .Talk to our academic expert!
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