A force of 100 N is applied on a block of mass 3 kg as shown in the figure. The coefficient of friction between the surface and the block is μ = 13. The acceleration of block is

Normal reaction on the block  N = 100 cos 300 = 50 3 N  ⇒fmax=μN = 50 N Vertical component of applied force = 100 sin 300 N =50 N Since weight of the block is equal to fmax , net force on the block is zero .