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Work
Question

A force of 5 N, making an angle θ with the horizontal, acting on an object displaces it by 0.4m along the horizontal direction. If the object gains kinetic energy of 1J, the horizontal component of the force (in N)  is

Easy
Solution

Work done on the body = K.E. gained by the body

FScosθ=1 Fcosθ=1s=10.4=2.5N

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