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The force required to stretch a steel wire of $1 {cm}^{2}$ cross-section to 1.1 times its length would be $(Y = 2 \times 10^{11} {Nm}^{- 2})$

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2×106 N

2×103 N

2×10−6N

2×10−7 N

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detailed solution

Correct option is A

F=A×Y× strain =1×10−4×2×1011×0.1=2×106N

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The force required to stretch a steel wire of 1 cm2 cross-section to 1.1 times its length would be (Y=2×1011 Nm−2)

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The force required to stretch a steel wire of $1 {cm}^{2}$ cross-section to 1.1 times its length would be $(Y = 2 \times 10^{11} {Nm}^{- 2})$