In forced oscillation of a particle, the amplitude is maximum for a frequency $ω_{1}$ while the energy is maximum for a frequency $ω_{2}$ of the force. then

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ω1<ω2

ω1>ω2

ω1<ω2 when damping is small and ω1>ω2 when damping is large

ω1=ω2

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Correct option is A

xe=F/mωe2−ω22+bωm2 amplitude is maximum when ω1=ω02−2g2 and energy is maximum when ω2=ωo

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A particle of mass m is attached to a spring of spring constant ‘k’ and has a natural frequency $ω_{o}$ . An external force F(t) proportional to $\cos ωt (ω \neq ω_{o})$ is applied to the oscillator. The maximum displacement of the oscillator will be proportional to

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In forced oscillation of a particle, the amplitude is maximum for a frequency ω1 while the energy is maximum for a frequency ω2 of the force. then

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In forced oscillation of a particle, the amplitude is maximum for a frequency $ω_{1}$ while the energy is maximum for a frequency $ω_{2}$ of the force. then