First slide

Second law

Question

A force-time graph for the motion of a body is shown in the figure. The change in the momentum of the body between zero and 10 sec is

Moderate

A

zero
B

4 kg m/s
C

5 kg m/s
D

3 kg m/s

Solution

As $F = \frac{dp}{dt}$
$\int dp = \int F dt$
$∆ p$ = area under F-t graph
$∆ p = \frac{1}{2} \times 8 \times 1 - 2 \times 0.5 = 3 kg m / s$

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