41 forks are so arranged that each produces 5 beats per sec when sounded with its near fork. If the frequency of last fork is double the frequency of first fork, then the frequencies of the first and last fork are respectively (in Hz)
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a
200, 400
b
205, 410
c
195, 390
d
100, 200
answer is A.
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Detailed Solution
Similar to previous question nLast = nFirst + (N – 1)x 2n = n + (41 – 1) 5⇒ nFirst = 200 Hz and nLast = 400 Hz