Four bodies of each mass ‘M’ are kept at the vertices of a square of side ‘x’ m. The resultant force on any mass is

The force on ‘C’ due  to mass at A,  B and D are F3,F1 and F2 respectively  F1=F2=GM2x2 ; F1=F12+F22  F3=GM22x2   F1=2F1 ∴θ=900  ∴ Net force on ‘M’ at ‘c’ isF=F3+F1F=F3+2F1F=GM22x2+2GM2x2F=GM22x22+12F=GM22x2(22+1)