Four capacitors and a switch S are connected to a source as shown in the figure. Initially, S is open and the capacitors are uncharged after S is closed and steady state is reached, the energy stored in the 4mF capacitor in the units of 10-5J is

From the diagram 10 μF and 10μF are series , Equivalent= 5 μF5μF and 5μF are in parallel  .Equivalent is 10 μFNow circuit has effectively two capacitors 4 μF and 10 μF connected in series with a 14V  batteryPotential across 4μF is 1410+410=10Venergy= 124×10-6×100= 20×10-5