First slide

Capacitance

Question

Four capacitors with capacitances $C_{1}$ = 1 mF, $C_{2}$ = 1.5 mF, $C_{3}$ = 2.5 mF and $C_{4}$ = 0.5 mF are connected as shown and are connected to a 30 volt source. The potential difference between points a and b is

Difficult

A

5 V
B

9 V
C

10 V
D

13 V

Solution

$r a t i o o f C_{1} : C_{2} = 2 : 3 i n s e r i e s p o t e n t i a l d i f f e r e n c e i s i n v e r s e l y p r o p o r t i o n a l t o t h e c a p a c i \tan c e p . d a c r o s s C_{1} = V_{A} - V_{a} = 30 x \frac{3}{5} = 18 V s i m i l a r l y r a t i o o f C_{3} : C_{4} = 5 : 1 a n d p . d a c r o s s C_{3} = V_{A} - V_{b} = 30 x \frac{1}{6} = 5 V$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App