Four charges are placed on corners of a square as shown in figure having side of 5 cm. If Q is one microcoulomb, then electric field intensity at centre will be

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1.02×107N/C upwards

2.04×107N/C downwards

2.04×107N/C upwards

1.02×107N/C downwards

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detailed solution

Correct option is A

Side a=5×10−2mHalf of the diagonal of the square r=a2Electric field at centre due to charge q E=kqa22Now field at O=E2+E2=E2=kqa22⋅2=9×109×10−6×2×25×10−22=1.02×107N/C (upward)

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Four charges are placed on corners of a square as shown in figure having side of 5 cm. If Q is one microcoulomb, then electric field intensity at centre will be

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