Questions
Four charges are placed on corners of a square as shown in figure having side of 5 cm. If Q is one microcoulomb, then electric field intensity at centre will be
detailed solution
Correct option is A
Side a=5×10−2mHalf of the diagonal of the square r=a2Electric field at centre due to charge q E=kqa22Now field at O=E2+E2=E2=kqa22⋅2=9×109×10−6×2×25×10−22=1.02×107N/C (upward)Talk to our academic expert!
Similar Questions
A pendulum bob of mass and carrying a charge is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
