In four complete revolution of the cap, the distance travelled on the pitch scale is 2 mm. If there are 50 divisions on the circular scale, then the least count of the screw gauge is
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a
0.001 mm
b
0.01 mm
c
0.10 mm
d
1.0 mm
answer is B.
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Detailed Solution
Pitch = Distance travelled on pitch scale Number of rotation =2 mm4=0.5 mm Least count = Pitch Number of division on circular scale =0.5 mm50=0.01 mm