First slide

Measurement

Question

In four complete rotations, the distance moved by the screw on the linear scale is $2 mm$ . circular scale contains 50 divisions. Find the least count of the screw gauge

Moderate

A

0.05 mm
B

0.01 mm
C

0.1 mm
D

0.02 mm

Solution

Pitch = $\frac{2}{4} = 0.5 mm$
Least count = $\frac{0.5}{50} = 0.01 mm$

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