Four equal charges Q are placed at the four comers of a square of each side is 'a'. Work done in removing a charge -Q from its centre to infinity is

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2Q24πε0a

2Q2πε0a

Q22πε0a

answer is C.

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Detailed Solution

Potential at centre O of the square,VO=4Q4πε0(a/2)Work done in shifting (- Q)charge from centre to infinityW=-QV∞-VO=QVO=42Q24πε0a=2Q2πε0a

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