First slide

Capacitance

Question

Four identical capacitors are connected in series with a 10 V battery as shown in the figure. Potentials at A and B are

Easy

A

10 V, 0 V
B

7.5 V, -2.5 V
C

5 V, -V
D

7.5V, 2.5 V

Solution

Let q = charge on each capacitor
$\frac{q}{C} + \frac{q}{C} + \frac{q}{C} + \frac{q}{C} = 10 \Rightarrow \frac{q}{C} = \frac{10}{4} \Rightarrow \frac{q}{C} = 2 .5 ∴ V_{A} - V_{N} = \frac{3 q}{C} = 3 \times 2 .5 = 7 .5 V V_{A} - 0 = 7 .5 V \Rightarrow V_{A} = 7 .5 V again V_{N} - V_{B} = \frac{q}{C} \Rightarrow 0 - V_{B} = 2 .5 V \Rightarrow V_{B} = - 2 .5 V$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App