Questions
Four identical capacitors are connected in series with a 10 V battery as shown in the figure. Potentials at A and B are
detailed solution
Correct option is B
Let q = charge on each capacitorqC+qC+qC+qC=10 ⇒ qC=104 ⇒ qC=2.5 ∴ VA−VN=3qC =3×2.5=7.5 V VA−0=7.5V ⇒ VA=7.5V again VN−VB=qC ⇒ 0−VB=2.5V ⇒ VB=−2.5VTalk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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