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Q.

Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual gravitational attraction. The speed of each particle will be :

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a

G1+22

b

1+22G2

c

G222−1

d

G21+22

answer is B.

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Detailed Solution

Net force on one particle Fnet =F1+2F2cos45∘= centripetalforce⇒GM2(2R)2+2GM2(2R)2cos45∘=MV2R⇒V=12GMR(1+22)⇒V=12G(1+22)

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Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual gravitational attraction. The speed of each particle will be :