Questions
Four identical thin rods each of mass M and length l form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is
detailed solution
Correct option is A
The moment of inertia of each rod about an axis through the centre of frame but perpenducular to frame =[its moment of inertia through its centre of mass and perpendicular to rod + (mass of rod) ×(perpendicular distance between two axes)]= Ml212+M(l2)2 = Ml23Moment of inertia of the system = Ml23×4= 43Ml2Talk to our academic expert!
Similar Questions
The moment of inertia of a circular disc of radius 2 m and mass 2 kg, about an axis passing through its centre of mass is 2 kg – . Its moment of inertia about an axis parallel to this axis and passing through its edge (in Kg -) is
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