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Four metallic plates, each with a surface area of one side A, are placed at a distance d apart from each other. The two inner plates are connected to point A and the other two plates to another point A as shown in fig. Then the capacitance of the system is

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a
ε0A/d
b
2ε0A/d
c
3ε0A/d
d
4ε0A/d

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detailed solution

Correct option is B

The two condensers in the middle are connected together .i.e., the connected plates act as a single conductor. In this way, effectively there are two capacitors connected inparallel. The capacity of each capacitor is given byC=ε0AdNet capacitance between A and B is given byCAB=C+C=2ε0A/d


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Two capacitors C1 and C2 having capacitance 2μF and 4μF respectively are connected as shown in the figure. Initially C1 has charge 4μC and C2 is uncharged. After long time closing the switch S :


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