Four metallic plates of each with a surface area of one side A, are placed at a distance d from each other. The alternate plates are connected to points A and B as shown in fig. The equivalent capacitance of the system will be
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a
ε0A/d
b
2ε0A/d
c
3ε0A/d
d
4ε0A/d
answer is C.
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Detailed Solution
The four plates are alternatively connected and form three capacitors in parallel. The capacity of each capacitor is (ε0A/d). Hence, the net capacitance between A and B is given by CAB=C+C+C=3ε0Ad