Four moles of CO2 at 327°C are mixed with six moles of Ne at 127°C. The final temperature of the mixture will be nearly

Carbon dioxide molecules have linear structure , hence Cv1=5R2 and Cv2=3R2 . Therefore, CVmix =n1CV1+n2CV2n1+n2=19R10  Now, n1CV1T1+n2CV2T2=n1+n2CVmix T ⇒ 4×5R2×600+6×3R2×400=10×19R10TT=505.26K or 232.26∘C