Four moles of a perfect gas heated to increase its temperature by 20C absorbs heat of 40 cal at constant volume. If the same gas is heated at constant pressure, the amount of heat supplied for the same rise in temperature is: (R = 2 cal / mol K)
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a
28 cal
b
56 cal
c
84 cal
d
94 cal
answer is B.
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Detailed Solution
At constant volume, heat required is nCvdT=40 n=4 and dT=2 so CV=5cal /mole/Kthen CP will be CV+R= 7 cal/mol/KHeat required will be 4 x7x2 =56 cal