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Four particles each of mass 0.5 kg are at the four corners of a square of side 2 m. The M.I of the system about a normal axis through centre of square is

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a

6 kgm2

b

1.2 kgm2

c

4 kgm2

d

2.5 kgm2

answer is C.

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Detailed Solution

M=0.5 g I=4(mr2) =4×0.5×(2)2 =4×510×2 I=4kg−m2

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