Four particles, each of mass 1kg, are placed at the corners of a square OABC of side 1m. ‘O’ is at the origin of the coordinate system. OA and OC are aligned along positive x-axis and positive y-axis respectively. The position vector of the centre of mass is (in ‘m’)
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a
i→ +j→
b
( i→+j→)/2
c
i→-j→
d
i→-j→2
answer is B.
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Detailed Solution
xcm=∑i=14mixi∑i=1i=4 here the position of the masses are (0,0),(1,0), (1,1), and (0,1) similarly ycm