Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is
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a
−32GML
b
−64GML2
c
Zero
d
32GML
answer is A.
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Detailed Solution
Potential at the centre due to single mass = −GML/2Potential at the centre due to all four masses =−4GML/2=−42GML=−32×GML