Four particles each of mass ‘m’ are placed at the corners of a light square frame of side length ' l '. The radius of gyration of the system about an axis perpendicular to the plane of square and passing through its centre is
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a
l2
b
l2
c
l
d
2l
answer is A.
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Detailed Solution
I=∑mr2=4ml22=4ml22=2ml2Radius of gyration k=IM=2ml24m=l2