Questions
Four particles of equal mass M move along a circle of radius .R under the action of their mutual gravitational attraction [Fig.]. The speed of each particle is
detailed solution
Correct option is D
The gravitational force on each particle due to other three particles provides the necessary centripetal force.GM2(2R)2cos45∘+GM2(2R)2cos45∘+GM2(2R)2=Mv2R2GM22R2×12+GM24R2=Mv2R2GM2R+GM4R=v2 ∴ v=GMR22+14Talk to our academic expert!
Similar Questions
Two particles each of mass m are placed at points A and C such that AB =BC =L as shown in fig.
The gravitational force on a third particle placed at D at a distance I metre on the perpendicular bisector of the line AC, is
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