Four particles of mass 1kg, 2kg, 3kg , 4kg are placed at the vertices of square of side 1m. The magnitude of force on 1kg mass is
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a
F=2G+3G222+4G+3G222
b
F=2G+3G222+4G−3G222
c
F=2G−3G222+4G+3G222
d
F=2G−3G222+4G−3G222
answer is A.
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Detailed Solution
Forces on 1 kg at ‘A’ isF3=G(1)(3)(2)2=3G2F1=G(1)(2)(1)2=2GF2=G(1)(4)(1)2=4GAlong ‘x’ direction; F1=F1+F3cos450 F1=2G+3G22Along ‘y’ direction F1=F2+F3sin450 =4G+3G22Resultant force at ‘A’ is F=F12+F112=2G+3G222+4G+3G222