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Four particles of masses $1, 1, 1, 1 k g$ are arranged at the corners A, B, C, D of a square ABCD of side 1m as shown in the figure. The perpendicular distance of their centre of mass from the side AB is

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detailed solution

Correct option is D

Sol. yCM=1×0+1×0+1×1+1×14 =24=0.5m

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Four particles of masses 1, 1, 1, 1kg are arranged at the corners A, B, C, D of a square ABCD of side 1m as shown in the figure. The perpendicular distance of their centre of mass from the side AB is

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Ready to Test Your Skills?

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Four particles of masses $1, 1, 1, 1 k g$ are arranged at the corners A, B, C, D of a square ABCD of side 1m as shown in the figure. The perpendicular distance of their centre of mass from the side AB is