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Q.

Four parties each of mass m are lying symmetrically on the rim of a disc of mass M and radiusR . MI of this system about an axis passing through one of the particles and ⊥ to plane of disc is

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a

16 m R2

b

(3 M+16 m) R22

c

(3 m+12 M) R22

d

Zero

answer is B.

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Detailed Solution

According to the theorem of ∥ axes, MI of disc about an axis passing through K and ⊥ to plane of disc is=12MR2+MR2=32MR2 Total MI of the system =32MR2+m(2R)2+m(2 R)2+m(2 R)2=(3M+16 m)R22 .

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