Four point charges are placed at the corners of a square with diagonal 2a as shown. What is the total electric field at the center of the square?

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kq/a2 at an angle of 450 above the +x-axis

kq/a2 at an angle of 450 below the –x axis

3kq/a2 at an angle of 450 above the –x-axis

3kq/a2 at an angle of 450 below the +x-axis

answer is B.

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Detailed Solution

At center electric field due to both 3q will be canceled. Now net field at center isE=E1−E2=k2q(a)2−kq(a)2=kq(a)2This is 450 below negative x-axis.

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