Four point charges 1μC,-2μC,3μC and -2μC are arranged on the four vertices of a square of side 1 cm. The dipole moment of this charge assembly is
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a
Zero
b
2×10-8C.m
c
22×10-8C.m
d
2×10-8C.m
answer is B.
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Detailed Solution
p→=∑qiri→ we can rearrange the charges to form three dipoles with charges as (-2 and +2) ,(+1 and _1) and (-1 and +1) with first and third in opposite direction and second one is perpendicular to them.