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Q.

Four point masses, each of value m , are placed at the corners of a square ABCD of sidel . The moment of inertia of the system about an axis passing through A and parallel to BD is

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a

3 ml2

b

3 ml2

c

ml2

d

2 ml2

answer is B.

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Detailed Solution

As is clear from AC=BD=l2+l2 =l2 Moment of inertia of four point masses about BDIBD=m(l22)2+m×0+m(l22)2+m×2l2       =ml22+ml22=2ml2=3ml2
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