Four positive point charges( +q) are kept at the four corners of a square of a side ' l '. The net electric field at the mid point of any one side of the square is, take 14πε0=K :
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a
4Kq12
b
16Kq5512
c
8Kq512
d
Kq12
answer is B.
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Detailed Solution
F1=14πε0q52l2=K4q5l2 F2=14πε0q52l2=K4q5l2Horizontal components cancel each other and net force is due to vertical components=F1sinθ+F2sinθ=24q512=1521=16Kq5512