Q.

Four resistances of 15 Ω, 12Ω , 4 Ω and 10Ω respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of 10Ω to balance the network is __________ Ω.

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Detailed Solution

Balancing Wheatstone bridge, 1510R10+R = 124⇒10R10+R×12=15×4 ⇒120R=600+60R⇒60R=600⇒ R= 10Ω

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Four resistances of 15 Ω, 12Ω , 4 Ω and 10Ω respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of 10Ω to balance the network is __________ Ω.