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Four thin rods of same mass M and same length l, form a square as shown in the figure. Moment of inertia of this system about an axis through centre O and perpendicular to its plane is

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By Expert Faculty of Sri Chaitanya
a
43Ml2
b
Ml23
c
Ml26
d
23Ml2
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detailed solution

Correct option is A

Moment of inertia of rod AB about point P=112Ml2M.I. of rod AB about point O=Ml212+Ml22=13Ml2[by the theorem of parallel axis]and the system consists of 4 rods of similar type so by the symmetry ISystem =43Ml2.


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A circular portion of diameter R is cut out from a uniform circular disc of mass M and radius R as shown in Fig. The moment of inertia of the remaining (shaded) portion of the disc about an axis passing through the centre O of the disc and perpendicular to its plane is

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