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Q.

Four uniform wires having equal length 1 m each and resistance in the ratio 1:2:3:4 are connected together to form a square CDEF in that order i.e. CD, DE, EF, FC and resistance of wire CD is ‘r’. This loop surrounds a cylindrical region of circular cross section in which uniform magnetic field whose net flux depends on time according to relation  ϕ=40 t weber, where ‘t’ is in second. The magnetic field is perpendicular to the plane of square loop. Centre of circular cross section and square loop coincides.(V1 &V2 are ideal voltmeters)

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a

Reading of voltmeters  V1 and  V2 are equal

b

Reading of voltmeter V1  is 8 Volt

c

Reading of voltmeter V2  is 16 Volt

d

The potential difference between point C and F is 16 Volt

answer is B.

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Detailed Solution

ε=−dϕdt=40 V​i=ε10r=4010r=4r​V1=2r×i​=8VV2=8r×i=32VVCF=4r×i=16VV1 and V2 are different because electric field in the loop is non-conservative.
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