First slide

combination of resistance

Question

Four wires of equal length and of resistance 10 $Ω$ each are connected in the form of a square. The equivalent resistance between two opposite corners of the square is

Moderate

A

10 $Ω$
B

4 $Ω$
C

1/4 $Ω$
D

1/8 $Ω$

Solution

Between the corners, there are two wires in parallel. The resistance of each wire is 2 x 10 ohm. Hence the resistance of combination will be
$\frac{1}{R} = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} or R = 10 Ω$

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