Q.

A frame of reference that is accelerated with respect to an inertial frame of reference is called a non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis with a constant angular velocity ω is an example of a non-inertial frame of reference. The relationship between the force F→rot  experienced by the particle of mass m moving on the rotating disc and the force Fin→ experienced by the particle in an inertial frame of reference is  F→rot=Fin→+2mv→rot×ω→+mω→×r→×ω→, where vrot→ is the velocity of the particle in the rotating frame of reference and r→ is the position vector of the particle with respect to the center of the discNow consider a smooth slot along a diameter of a disc of radius R rotating counter-clockwise with a constant angular speed  ω about its vertical axis through its center. We assign a coordinate system with the origin at the center of the disc, the x-axis along the slot, the y-axis perpendicular to the slot and the z-axis along the rotation axis ω→=ωk^ . A small block of mass m is gently placed in the slot at  r→=R/2i^ at t=0  and is constrained to move only along the slot The distance r of the block at time t is The net reaction of the disc on the block is

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answer is [OBJECT OBJECT], [OBJECT OBJECT].

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Detailed Solution

From the frame of disc the block is constrained to move radially outward due to centrifugal force.F→rkt=m[(ω→×r→)×ω→]=mrω2i^⇒a=rω2⇒vdvdr=rω2⇒∫0V vdr=ω2∫R2r rdr⇒v2=ω2r2−R24⇒v=ωr2-R22Now , dr=vdt⇒dr=ωr2−R22dt⇒∫R2r drR2r2−R22=ω∫0t dt⇒cosh−1⁡2rR=ωt⇒2rR=cosh⁡(ωt)⇒r=R2eωt+e−ωt2=R4eωt+e−ωt F→rot=F→in+2mv→rot×ω→+m(ω→×r→)×ω→=−mω2ri^+2mvrotω(−j^)+mω2ri^=−2mvrotωj^here vrot=drdt=ωR4eωt−e−ωtF→rot =−mω2R2eωt−e−ωtj^The reaction force on block due to walls of disc will be −F→rot The net reaction force will beR→=R→wall +R→ground =mω2R2eωt−e−ωtj^+mgk^
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