A frame of reference that is accelerated with respect to an inertial frame of reference is called a non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis with a constant angular velocity ω is an example of a non-inertial frame of reference. The relationship between the force F→rot experienced by the particle of mass m moving on the rotating disc and the force Fin→ experienced by the particle in an inertial frame of reference is F→rot=Fin→+2mv→rot×ω→+mω→×r→×ω→, where vrot→ is the velocity of the particle in the rotating frame of reference and r→ is the position vector of the particle with respect to the center of the discNow consider a smooth slot along a diameter of a disc of radius R rotating counter-clockwise with a constant angular speed ω about its vertical axis through its center. We assign a coordinate system with the origin at the center of the disc, the x-axis along the slot, the y-axis perpendicular to the slot and the z-axis along the rotation axis ω→=ωk^ . A small block of mass m is gently placed in the slot at r→=R/2i^ at t=0 and is constrained to move only along the slot The distance r of the block at time t is The net reaction of the disc on the block is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is [OBJECT OBJECT], [OBJECT OBJECT].
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
From the frame of disc the block is constrained to move radially outward due to centrifugal force.F→rkt=m[(ω→×r→)×ω→]=mrω2i^⇒a=rω2⇒vdvdr=rω2⇒∫0V vdr=ω2∫R2r rdr⇒v2=ω2r2−R24⇒v=ωr2-R22Now , dr=vdt⇒dr=ωr2−R22dt⇒∫R2r drR2r2−R22=ω∫0t dt⇒cosh−12rR=ωt⇒2rR=cosh(ωt)⇒r=R2eωt+e−ωt2=R4eωt+e−ωt F→rot=F→in+2mv→rot×ω→+m(ω→×r→)×ω→=−mω2ri^+2mvrotω(−j^)+mω2ri^=−2mvrotωj^here vrot=drdt=ωR4eωt−e−ωtF→rot =−mω2R2eωt−e−ωtj^The reaction force on block due to walls of disc will be −F→rot The net reaction force will beR→=R→wall +R→ground =mω2R2eωt−e−ωtj^+mgk^
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
A frame of reference that is accelerated with respect to an inertial frame of reference is called a non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis with a constant angular velocity ω is an example of a non-inertial frame of reference. The relationship between the force F→rot experienced by the particle of mass m moving on the rotating disc and the force Fin→ experienced by the particle in an inertial frame of reference is F→rot=Fin→+2mv→rot×ω→+mω→×r→×ω→, where vrot→ is the velocity of the particle in the rotating frame of reference and r→ is the position vector of the particle with respect to the center of the discNow consider a smooth slot along a diameter of a disc of radius R rotating counter-clockwise with a constant angular speed ω about its vertical axis through its center. We assign a coordinate system with the origin at the center of the disc, the x-axis along the slot, the y-axis perpendicular to the slot and the z-axis along the rotation axis ω→=ωk^ . A small block of mass m is gently placed in the slot at r→=R/2i^ at t=0 and is constrained to move only along the slot The distance r of the block at time t is The net reaction of the disc on the block is