Questions
In Fraunhoffer diffraction pattern width of central bright fringe is . If wavelength of light is doubled and slit width is halved, distance of second dark fringe from the centre of central bright fringe is
detailed solution
Correct option is A
If ‘a’ be the width of the slit and λ be the wavelength of light used. Then β=2λa. In the second case width of central maxima is β1=2λ1a1=22λa2=42λa=4β∴ Width of first secondary maxima =β12=2β∴ Distance of second dark fringe = Half of the width of central bright fringe + width of first secondary bright fringe=β12+β12=β1=4βTalk to our academic expert!
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A screen is placed 50cm from a single slit, which is illuminated with 6000 light. If distance between the first and third minima in the diffraction pattern is 3mm, the width of the slit is
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