First slide

Diffraction

Question

In Fraunhoffer diffraction, width of slit is 0.01 mm and wavelength of light used is 500 nm. Geometrical optics is valid upto a distance x from the plane of slit. Then x is

Moderate

A

10 mm
B

1 mm
C

0.01 mm
D

0.1 mm

Solution

If ‘a’ be the slit width and $λ$ be the wavelength of light used, then
$x = \frac{a^{2}}{2 λ} = \frac{{(0 .01)}^{2}}{2 \times 500 \times 10^{- 9} \times 10^{3}} mm = 0 .1 mm$

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