In Fraunhoffer diffraction, width of slit is 0.01 mm and wavelength of light used is 500 nm. Geometrical optics is valid upto a distance x from the plane of slit. Then x is
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a
10 mm
b
1 mm
c
0.01 mm
d
0.1 mm
answer is D.
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Detailed Solution
If ‘a’ be the slit width and λ be the wavelength of light used, then x=a22λ=0.0122×500×10−9×103mm=0.1 mm