A free body of mass 8 kg is travelling at 2 meter per second in a straight line. At a certain instant, the body splits into two equal parts due to internal explosion which releases 16 joules of energy(totally taken as KE). Neither part leaves the original line of motion finally

As the body splits into two equal parts due to internal explosion therefore momentum of system remains conserved i.e. 8×2=4v1+4v2    ⇒v1+v2=4          …(i) By the law of conservation of energy Initial kinetic energy + Energy released due to explosion= Final kinetic energy of the system ⇒12×8×(2)2+16=124v12+124v22⇒v12+v22=16                                     …(ii) By solving eq. (i) and (ii) we get  v1=4  and   v2=0i.e. one part comes to rest and other moves in the same direction as that of original body.