Questions
A free nucleus of mass 24 amu emits a gamma photon (when initially at rest). The energy of the photon is 7 MeV. The recoil energy of the nucleus in keV is
detailed solution
Correct option is B
2mk=Ec⇒k=E22mc2=(7MeV)22×24×1.67×10−27×(3×108)2=1.1KeVTalk to our academic expert!
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The daughter nuclei are unstable therefore they decay into stable end products by successive emission of β-particles. Let mass of amu, mass of amu, mass of amu, mass of = 97.9054
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