First slide

Release from certain height

Question

A freely falling body traveled xm in n^th second distance travelled in (n - 1)^th second is

Easy

A

x
B

x + g
C

x - g
D

2x + 3g

Solution

For a freely falling body distance moved in n^thsecond $\large x_n = \frac{1} {2}g(2n - 1)$ and in (n - 1)^th second, $\large x_{n - 1} = \frac{1} {2}g[2(n - 1) - 1]$
$\large \therefore x_{n - 1} = \frac{1} {2}g[(2n - 1) - 2] = (x - g)$

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