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Q.

The frequencies of two sound sources are 256 Hz and 260 Hz. At t = 0, the intensity of sound is maximum. Then the phase difference at the time t = 1/16 sec will be

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a

Zero

b

π

c

π/2

d

π/4

answer is C.

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Detailed Solution

Time interval between two consecutive beats T=1n1−n2=1260−256=14sec   so,  t=116=T4  sec By using time difference = T2π× Phase difference    ⇒T4=T2π×φ⇒φ=π2
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The frequencies of two sound sources are 256 Hz and 260 Hz. At t = 0, the intensity of sound is maximum. Then the phase difference at the time t = 1/16 sec will be