Questions
The frequencies of two sound sources are 256 Hz and 260 Hz. At t = 0, the intensity of sound is maximum. Then the phase difference at the time t = 1/16 sec will be
detailed solution
Correct option is C
Time interval between two consecutive beats T=1n1−n2=1260−256=14sec so, t=116=T4 sec By using time difference = T2π× Phase difference ⇒T4=T2π×φ⇒φ=π2Talk to our academic expert!
Similar Questions
A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.
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