The frequency f of vibrations of a mass m suspended from a spring of spring constant k is given by f = Cmxky, where C is a dimensionless constant. The values of x and y are, respectively,
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a
12,12
b
−12,−12
c
12,−12
d
−12,12
answer is D.
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Detailed Solution
f = Cmxky. Writing dimensions on both sides, M0L0T−1=MxML0T−2y=Mx+yT−2yComparing dimensions on both sides, we have 0=x+y and −1=−2y ⇒ y=12, x=−12Aliter. Remembering that the frequency of oscillation of loaded spring is f=12πkm=12π(k)1/2m−1/2which gives x=−12 and y=12