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Q.

The frequency f of vibrations of a mass m suspended from a spring of spring constant k is given by f=Cmxky, where C is a dimensionless constant. The values of x and y are, respectively,

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a

12,12

b

−12,−12

c

12,−12

d

−12,12

answer is D.

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Detailed Solution

force constant K=F∆xf=Cmxky. Writing dimensions on both sides,M0L0T−1=MxML0T−2y=Mx+yT−2yComparing dimensions on both sides, we have0=x+y and −1=−2y ⇒y=12,x=−12Aliter. Remembering that the frequency of oscillation of loaded spring isf=12πkm=12π(k)1/2m−1/2 which gives x=−12 and y=12
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